Question

(x/2 - 2/3y)³ expand using suitable identity ​

Answer 1

Answer:

$we \: know \: that$

$\: (x - {y})^{3} = ( {x})^{3} - ({y})^{3} - 3 \times x \times y(x - y)$

(x/2 - 2/3y)³= (x/2)³ - (2/3y)³ - 3×x/2×2/3y (x/2 - 2/3y)

= x³/8 - 3/27y³ - 6x/6y (x/2- 2/3y)

= x³/8 - 8/27y³ - 6x²/12y + 12x²/18y²