(x/2-2/5) (2/5-x/2)-x
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Answered by
8
Hi ,
( x/2 - 2/5 )( 2/5 - x/2 ) - x
= - ( x/2 - 2/5 )( x/2 - 2/5 ) - x
= - ( x/2 - 2/5 )² - x
= - [( x/2 )²+( 2/5 )²-2 × x/2 × 2/5]-x
= -[ x²/4+4/25-2x/5 ] - x
= -x²/4 + 2x/5 - 4/25 - x
= -x²/4 + ( 2/5 - 1 )x - 4/25
= -x²/4 +[ (2 - 5 )/5]x - 4/25
= -x²/4 - 3x/5 - 4/25
I hope this helps you.
: )
( x/2 - 2/5 )( 2/5 - x/2 ) - x
= - ( x/2 - 2/5 )( x/2 - 2/5 ) - x
= - ( x/2 - 2/5 )² - x
= - [( x/2 )²+( 2/5 )²-2 × x/2 × 2/5]-x
= -[ x²/4+4/25-2x/5 ] - x
= -x²/4 + 2x/5 - 4/25 - x
= -x²/4 + ( 2/5 - 1 )x - 4/25
= -x²/4 +[ (2 - 5 )/5]x - 4/25
= -x²/4 - 3x/5 - 4/25
I hope this helps you.
: )
Answered by
0
(x/2 - 2/5 )( 2/5 - x/2) - x
= -(x/2 - 2/5 )( x/2 - 2/5) - x
= -(x/2 - 2/5)² - x
= - [( x/2 )²+( 2/5 )²-2 × x/2 × 2/5]-x =
=-[x²/4+4/25-2x/5] - x
= = -x²/4 + 2x/5-4/25 - x
-x²/4 + (2/5 - 1)x - 4/25
= = -x²/4 +[ (2 - 5)/5]x - 4/25
= -x²/4 - 3x/5-4/25
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