Question

x^2-(2-√5)x-2√5 solve by factorisation method

Answer 1

${x}^{2} - (2 - \sqrt{5} )x - 2 \sqrt{5}$

$= {x}^{2} - 2x + \sqrt{5} x - 2 \sqrt{5}$

$= x(x - 2) + \sqrt{5} (x - 2)$

$= (x - 2)(x + \sqrt{5} )$

$x \: \: can \: \: be \: \: either \: \: 2 \: \: or \: \: - \sqrt{5}$