Question

(x-2)²+8x
class 8 factorisation​

Answer 1

Answer:

Given that: x

2

+6x+8

=x

2

+4x+2x+8, (split middle term)

=(x

2

+4x)+(2x+8), (group pair of terms)

=x(x+4)+2(x+4), (factor each binomials)

=(x+4)(x+2), (factor out common factor (x+4)

Hence factors of x

2

+6x+8 are (x+4)(x+2)

Answer 2

$\huge\underline\frak\orange{ϙᴜᴇsᴛɪᴏɴ:-}$

ғᴀᴄᴛᴏʀɪsᴇ - (x-2)² + 8x

$\huge\underline\frak\orange{AnsWer:-}$

Fᴏʟʟᴏᴡɪɴɢ ɪs ᴛʜᴇ ғᴀᴄᴛᴏʀɪsᴀᴛɪᴏɴ ᴏғ ᴛʜᴇ ɢɪᴠᴇɴ ᴇxᴘʀᴇssɪᴏɴ-

$= {(x - 2)}^{2} + 8x \\ = {x}^{2} - 2.x.2 + {2}^{2} + 8x \\ = {x}^{2} - 4x + 4 + 8x \\ = {x}^{2} + 4x + 4 \\ = {x}^{2} + (2 + 2)x + 4 \\ = {x}^{2} + 2x + 2x + 4 \\ = x(x + 2) + 2(x + 2) \\ = (x + 2)(x + 2) \\ therefore \: x = - 2$

ᴛʜᴀɴᴋ ʏᴏᴜ☺️✌️..