Question

x^2 - 2(a + 2)x + (a+1) (a+3) = 0

Answer 1

a =7/2

ANSWER.........

Answer 2

Hello dear..

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Answer:

Step-by-step explanation:

X^2 - 2(a + 2)x + (a+1) (a+3) = 0

b^2-4ac = 0

{-2(a+2)}^2 -4 (1)(a+1)(a+3) =0

(-2a-4)^2 -4(a^2+4a+3)=0

Use formula (a-b)^2 =a^2+b^2-2ab for the equation (-2a-4)^2

4a^2-8a+16-4a^2+16a-12=0

8a+4=0

a= -4/8

a= -1/2

Hope it helps..✌✌