Question

x+ 2/2.x^2 + 6x+5
find integral​

Answer 1

Answer:

1/2 logx - 1/x + 3x²  + 5x +c

Step-by-step explanation:

x+ 2/2.x^2 + 6x+5

=(x/2x²) + (2/2x²) + 6x +5

=(1/2x) + (1/x²) + 6x +5

integrating wrt x;

=1/2 logx + (-1/x) + 6x²/2 + 5x +c [where c is the integration constant]

=1/2 logx - 1/x + 3x²  + 5x +c