Question

x^2+2√x-3=0 . Solve this quadratic equation

Answer 1

Answer:

do ask google baba this answer

Answer 2

Answer:

$this \: is \: a \: quadratic \: equation$

Step-by-step explanation:

$if \: question \: like \: this \\ {x}^{2} + 2x - 3 = 0 \\ then \\ x = \frac{ - 2 + \sqrt{4 - ( - 3 \times 4 \times 1)} }{2 \times 1} \\ = \frac{ - 2 + 2 \sqrt{2} }{2} = - 1 + \sqrt{2 } \\ or - 1 - \sqrt{2}$