Question

x^2 +√2 x -4=0 where x = -2√2

Answer 1

Answer:

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Step-by-step explanation:

Given :-

${x}^{2} + \sqrt{2} \: x - 4 = 0$

$if \: x = - 2 \sqrt{2}$

Solving :-

then

$now \: substitute \: x \: value \: in \: the \\ \: given \: equation \: we \: get$

${x}^{2} + \sqrt{2} \: x - 4 = 0 \\ = > ( { - 2 \sqrt{2} )}^{2} +\sqrt{2}( - 2 \sqrt{2} ) - 4 = 0 \\ = > 8 - 4 - 4 = 0 \\ = > 8 - 8 = 0 \\ = > 0 = 0$

therefore we can say that -2√2 is the root of the equation x²+√2x-4=0