Question

(x-2)^2+(x-4)^2=x^2​

Answer 1

Step-by-step explanation:

${(x - 2)}^{2} + {(x - 4)}^{2} = {x}^{2}$

${x}^{2} - 4x + 4 + {x}^{2} - 8x + 16 = {x}^{2}$

${x}^{2} - 12x + 20 = 0$

${x}^{2} - 10x - 2x + 20 = 0$

$x(x - 10) - 2(x - 10) = 0$

$(x - 2)(x - 10) = 0$

Therefore

$x = 2 \: or \: x = 10$

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