Question

(x-2)^2+(x+y)^2=0, find the value of y

pls step by step ans ans no spam​

Answer 1

Answer:

here is ur answer

Step-by-step explanation:

Given,

(x−a)2+(y-a)2

=0.

Since the sum of two positive numbers is 0 then they must be equal to 0 individually.

So, x−1=0⇒x=a.

Similarly y=a.

Now

yx=aa

=1.

Hope it's helpful.