Question

(x-2)^2+(x-y)^2=0 value of y​

Answer 1

Answer:

The value of y cannot really be found.

Step-by-step explanation:

Although,

y^2=2xy-x^2

But that's not the answer you want.

Answer 2

${\underline{\underline{\Huge{\mathfrak{Answer}}}}}$

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✩ SOLUTION :-

$\implies \: {(x - 2)}^{2} + {(x - y)}^{2} = 0 \\ \\ \implies \: {x}^{2} + 4 - 4x + {x}^{2} + {y}^{2} - 2xy = 0 \\ \\ \implies \: 2 {x}^{2} + {y}^{2} - 2xy - 4x + 4 = 0$

There is some error in question.

Hope it helps you ❤️