Question

(x-2)^2+(y-1÷2)^2=0 then the value of x÷y​

Answer 1

Answer:

2

Step-by-step explanation:

(x-2)^2+(y-1÷2)^2=0

if sum of two square numbers is 0,then

ex: x^2+y^2=0,then

x=0 and y=0.

then,(x-2)^2 =0

x-2=0

x=2.

(y-1÷2)^2=0

y-1=0÷2

y-1=0

y=1

thenx÷y=

=2÷1

=2

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