Question

x^2 + 200x = 1664
Find x

Answer 1

$\huge \: \red{ \: answer}$

${x}^{2} + 200x = 1664$

$\implies \: {x}^{2} + 200x - 1664 = 0$

$do \: the \: lcm$

$\implies \: {x}^{2} + 208x \: - 8x - 1664 = 0$

$\implies \: x(x + 208) \: - 8(x + 208) = 0$

$\implies \: (x + 208) (x + 8) = 0$

$so \: the \: values \: of \: x \: are$

$\boxed{( - 208 \: and \: 8)}$