Question

x^2-200x+4800find the roots

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Answer 1

x²-200x+4800

By quadratic formula method

D = b²-4ac

D= (-200)²-4(1)(4800)

D = 40000-19200

D= 20800

Now,

x = - b ±√D/2a

x = - (-200) ±√20800/2

x = 200 ±40√13/2

x = 200 +40√13/2 x = 200-40√13/2

x = 40(5 +√13)/2 x = 40(5-√13)/2

x =20(5+√13) x =20(5-√13)

Thus the zeros of quadratic equation is 20(5+√13) and 20(5-√13)

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