Question

x^2+20x-240
factorize this​

Answer 1

${x}^{2} + 20x - 240 = 0 \\ \\ a = 1 \\ \\ b = 20 \\ \\ c = - 240 \\ \\ \\ \\ x = \frac{ - b± \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ = \frac{ - 20± \sqrt{ {( - 20)}^{2} + 4 \times 1 \times 240} }{2 \times 1} \\ \\ = \frac{ - 20± \sqrt{400 + 1060} }{2} \\ \\ = \frac{ - 20± \sqrt{1460} }{2} \\ \\ = \frac{ - 20±2 \sqrt{365} }{2}$



Now,

$x = \frac{ - 20 + 2 \sqrt{365} }{2} \\ \\ = \frac{2( - 10 + \sqrt{365}) }{2} \\ \\ = - 10 + \sqrt{365}$


Again,

$x = \frac{ - 20 - 2 \sqrt{365} }{2} \\ \\ = \frac{2( - 10 - \sqrt{365} )}{2} \\ \\ = - 10 - \sqrt{365}$