Question

x^2-20x-a^2-b^2=0
Solve for value of x

Answer 1

Answer:

Step-by-step explanation:X^2-20x-a^2-b^2=0

then by applying the quadratic formula for solving quadratic equation

we get x=40±√400-4{-a^2-b^2}÷2

then we get x=20±√100+a^2+b^2    {we got this by dividing 2}

                       x=20±√100+a^2+b^2

now we x^2-20x-a^2-b^2=0    --------1

then x^2-20x = a^2+b^2                        {by adding 100 on both sides}

we get {x-10]^2=a^2+b^2 +100            

then using this in equation 1

we get x=20±{x-10}

then we get two cases where

case1  x=20+{x-10}

we will not get the ans

case 2 x=20-{x-10}

then we get 2x=30

x=15 this is ur answer