Question

x^{2}-21x+108. factorize it.....​

Answer 1

$x^{2}-21x+108 \\ x^{2}-12x-9x+108=0 \\ x(x-12)-9(x-12)=) \\ (x-12)(x-9)=0 \\ x=12,x=9$

Answer 2

Answer:

x²-12x+9x+108

x(x-12)-9(x-12)

x-9 or x-12

x=9 0r x=12