Question

x^2+25x+126 factorize the pr​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Given :-

${x}^{2} + 25x + 126 = 0$

What to find out =Roots of the equation?

Solution :-

Factorise by splitting middle term

${x}^{2} + 25x + 126 = 0 \\ \\ {x}^{2} + 18x + 7x + 126 = 0 \\ \\ x(x + 18) + 7(x + 18) = 0 \\ \\ (x + 18)(x + 7) = 0$

Now split it into possible cases

$(x + 18) = 0 \\ \\ (x + 7) = 0$

Hence,

$x_1 =( - 18) \\ \\ x_2 = ( - 7)$

Extra information :-

• A quadratic equation is an equation of the second degree, meaning it contains at least one term that is squared. The standard form is ax² + bx + c = 0 with a, b, and c being constants, or numerical coefficients, and x is an unknown variable.