Question

(X+2) (27-x)=210 solve this​

Answer 1

$\huge\text\red{\underline{\underline{Answer}}}$

$\bf (x+2)(27-x)=210$

$\bf x(27-x)+2(27-x)=210$

$\bf 27x-x²+54-2x=210$

$\bf 27x-2x-x²+54-210=0$

$\bf 25x-x²-156=0 \:\:\:\:[Rearranging \:\: terms]$

$\bf x²-25x+156=0$

$\bf x²-13x-12x+156=0 \:\:\:\: [By \:\: Factorisation]$

$\bf x(x-13)-12(x-13)=0$

$\bf (x-12)(x-13)=0$

$\bf\red{ 12 \:\: and \:\: 13 \:\: are \:\: the \:\: roots}$

Answer 2

Answer:

x=13, -12

Step-by-step explanation