Question

x^2-27x+182=0 solve this

Answer 1

solution of the question given above

Answer 2

$Given \: Quadratic \: Equation : \\x^{2} - 27x + 182 = 0$

/* Splitting the middle term, we get */

$\implies x^{2} - 13x - 14x + 182 = 0$

$\implies x(x - 13) - 14(x - 13) = 0$

$\implies (x - 13)(x - 14) = 0$

$\implies (x - 13) = 0 \:Or \: (x - 14) = 0$

$\implies x = 13 \:Or \: x = 14$

Therefore.,

$\green { x = 13 \:Or \: x = 14 }$

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