x^ 2 + 27x - 182 :- factorize
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Answered by
12
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Step 1 :Trying to factor by splitting the middle term
1.1 Factoring x2+27x-182
The first term is, x2 its coefficient is 1 .
The middle term is, +27x its coefficient is 27 .The last term, "the constant", is
-182
Step-1 : Multiply the coefficient of the first term by the constant 1 • -182 = -182
Step-2 : Find two factors of -182 whose sum equals the coefficient of the middle term, which is 27 .
-182 + 1 = -181
-91+ 2 = -89
-26 + 7 = -19
-14 + 13 = -1
-13 + 14 = 1
-7 + 26 = 19
-2 + 91 = 89
-1 + 182 = 181
Observation : No two such factors can be found !! Conclusion : Trinomial can not be factored
Final result : x2 + 27x - 182
==============================================
Hope my answer helped … ☺
Nice Questions! ♥
Let's unlock the answers now…
==============================================
⇔
Step 1 :Trying to factor by splitting the middle term
1.1 Factoring x2+27x-182
The first term is, x2 its coefficient is 1 .
The middle term is, +27x its coefficient is 27 .The last term, "the constant", is
-182
Step-1 : Multiply the coefficient of the first term by the constant 1 • -182 = -182
Step-2 : Find two factors of -182 whose sum equals the coefficient of the middle term, which is 27 .
-182 + 1 = -181
-91+ 2 = -89
-26 + 7 = -19
-14 + 13 = -1
-13 + 14 = 1
-7 + 26 = 19
-2 + 91 = 89
-1 + 182 = 181
Observation : No two such factors can be found !! Conclusion : Trinomial can not be factored
Final result : x2 + 27x - 182
==============================================
Hope my answer helped … ☺
sanchit29:
it is not x2 it is x ki power 2
Answered by
21
actually the question should be x^2 +27x + 182
so, x^2 +27x + 182 = x^2 + 13x +14x +182 = x(x+13) + 14(x+13) = (x+13) (x+14)
Thus, the factors are (x+13) and (x+14)
Hope this helps you...
so, x^2 +27x + 182 = x^2 + 13x +14x +182 = x(x+13) + 14(x+13) = (x+13) (x+14)
Thus, the factors are (x+13) and (x+14)
Hope this helps you...
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