Question

x^2 - 28x + 192 = 0
find the value of x

Answer 1

x^2 - 28x + 192 = 0

x^2 - 16x - 12x + 192=0

x(x - 16) - 12(x - 16) = 0

(x - 12) (x - 16) = 0

x - 12 = 0 ; x - 16 = 0

x = 12 ; x = 16