Question

x^2 - 29x + 120 = 0 where x is the denominator

Answer 1

x2 - 24x - 5x - 120

x • (x-24)

5 • (x-24)

(x-5) • (x-24)

(x - 5) • (x - 24) = 0

x = 24

x = 5

Answer 2

≡QUESTION≡

Find x in the equation x²- 29x + 120 = 0, where x is the zero of the polynomial.

                                                       

║⊕ANSWER⊕║

Given equation,

$x^{2} -29x+120=0$

Solving, we get,

$x^{2} -24x-5x+120=0\\x(x-24)-5(x-24)=0\\(x-5)(x-24)=0$

Now,

$x-5=0\\=> x = 5$

$x-24=0\\=> x = 24$

∴ The zeroes are 5 and 24.