Math, asked by shraddhapatil79, 11 months ago

x^2 -2ax+(a^2-b^2)plzz solve​

Answers

Answered by Amsusmita04
0

just solve

Step-by-step explanation:

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Answered by AlluringNightingale
0

Answer:

x = a + b OR x = a - b

Note:

★ The possible values of the variable for which the polynomial becomes zero are called its zeros.

★ To find the zeros of the polynomial p(x) , operate on p(x) = 0 .

★ A quadratic polynomial can have atmost two zeros .

★ If α and ß are the zeros of the quadratic polynomial ax² + bx + c , then ;

• Sum of zeros , (α + ß) = -b/a

• Product of zeros , (αß) = c/a

★ If α and ß are the zeros of any quadratic polynomial , then it is given by ;

x² - (α + ß)x + αß

★ If α and ß are the zeros of the quadratic polynomial ax² + bx + c , then they (α and ß) are also the zeros of the quadratic polynomial k(ax² + bx + c) , k≠0.

Solution:

Here,

The given quadratic polynomial is ;

x² - 2ax + (a² - b²)

Now,

In order to find the zeros of the given quadratic polynomial let's equate it to zero and further using factorisation by middle term splitting method , let's find the zeros .

Thus,

=> x² - 2ax + (a² - b²) = 0

=> x² - (a + a)x + (a² - b²) = 0

=> x² - (a + b + a - b)x + (a + b)(a - b) = 0

=> x² - (a + b)x - (a - b)x + (a + b)(a - b) = 0

=> x•[ x - (a + b) ] - (a - b)•[ x - (a + b) ] = 0

=> [ x - (a + b) ]•[ x - (a - b) ] = 0

=> x - (a + b) = 0 OR x - (a - b) = 0

=> x = a + b OR x = a - b

Hence,

The required answer is ;

x = a + b OR x = a - b

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