Question

x^2-(2b-1)x+(b^2-b-20)=0

Answer 1

first we will solve b^2-b-20
so, b^2-(5-4)b-20=0
b^2-5b+4b-20=0
b(b-5)+4(b-5)=0
b+4=0,b-5==0
b=-4, b=5
now solve , x^2-(2b-1)x+b^2-b-20