Question

x^2-(2b-1)x+(b^2-b-20)=0 find the roots of this quadratic equation by factorization method

Answer 1

x^2-(2b-1)x+(b^2-b-20)=0

=>x^2-2(b-1/2)x+(b^2-b+1/4)-20.25=0

=>{x-(b-1/2)}^2-(4.5)^2=0

=>(x-b+0.5)^2-(4.5)^2=0

=>(x-b+0.5-4.5)(x-b+0.5+4.5)=0

=>(x-b-4)(x-b+5)=0

=>x=b+4 and b-5

Answer 2

Hey mate!!!!

This sum can easily be solved by splitting the middle term:

x^2 - (b-5)x + (b+4)x + (b^2-b-20) =0

x [x-(b-5)] + [(b+4) x+ (b-5)]=0

x = b-5. OR
x = b+4


Hope u understand!

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