Question

x^2-(2b-1)x+(b^2-b-20)=0 solve for X for 10th students​

Answer 1

Answer:

x²-(2b−1)x+b

2

−b−20=0

The roots are:

x=

2

(2b−1)±

(2b−1)

2

−4×(b

2

−b−20)

=

2

(2b−1)±

4b

2

+1−4b−4b

2

+4b+80

=

2

(2b−1)±

81

=

2

(2b−1)±9

∴x=

2

2b−1+9

=b+4

or,x=

2

2b−1−9

=b−5