Question

X^2+(2k+3)x+k^2=o and the two roots are real and equals then the value of k =

Answer 1

Step-by-step explanation:

x² + (2k+3)+k² = 0

For the roots to be real and equal,

D=0

(2k+3)² - 4×k²×1 = 0

4k² + 9 + 12k -4k² = 0

12k=-9

k = -3/4