Math, asked by BlackCell3504, 1 year ago

X^2+2kx-3
find the value of (k) of x=-1/2

Answers

Answered by DEVINEQUEEN
0

Answer:

X^2 + 2kx - 3 =0

=>(-1/2)^2 + 2×k×(-1/2) -3 =0

=>1/4+(-2k/2 -3=0

=>1/4 -2k/2-3=0

=>1-4k-12=0

----------------

4

=> 1-4k-12 =0

=>-11-4k=0

=> -4k =11

=> k= -11/4................answer........

Answered by lidyamulugetamewa
0

Step-by-step explanation:

=x²+2kx-3=0

=(-1/2)²+2(k)(-1/2)-3=0

=0.25-1k-3=0

= -2.75=k

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