X^2+2kx-3
find the value of (k) of x=-1/2
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Answered by
0
Answer:
X^2 + 2kx - 3 =0
=>(-1/2)^2 + 2×k×(-1/2) -3 =0
=>1/4+(-2k/2 -3=0
=>1/4 -2k/2-3=0
=>1-4k-12=0
----------------
4
=> 1-4k-12 =0
=>-11-4k=0
=> -4k =11
=> k= -11/4................answer........
Answered by
0
Step-by-step explanation:
=x²+2kx-3=0
=(-1/2)²+2(k)(-1/2)-3=0
=0.25-1k-3=0
= -2.75=k
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