Question

x^2 +2root 3x-9=0 quadratic​

Answer 1

Answer:

${x}^{2} + 2 \sqrt{3} x - 9 = 0 \\ = > {x}^{2} + 3 \sqrt{3} x - \sqrt{3} x - 9 = 0 \\ = > x(x + 3 \sqrt{3} ) - \sqrt{3} (x + 3 \sqrt{} 3) = 0 \\ = > (x + 3 \sqrt{3} )(x - 3 \sqrt{3)} = 0 \\ = > either(x + 3 \sqrt{3} ) = 0 \: or \: (x - 3 \sqrt{3} ) = 0 \\ = > x = - 3 \sqrt{3 \: } or \: x = 3 \sqrt{3}$