Question

X^2 + 2root2 k +18 has equal root find k

Answer 1

Answer:

$it \: \: have \: \: equal \: \: roots \: \: so \: \: d = 0 \\ \\ {b}^{2} - 4ac = 0 \\ \\ {0}^{2} - 4 \times 1 \times (2 \sqrt{2} k + 18) = 0 \\ \\ k = - \frac{9}{ \sqrt{2} }$