x^2+2root3x+3=0 by quadratic equation
Attachments:
Answers
Answered by
9
Hey
Here is your answer,
x^2 + 2√3x + 3=0
x^2 +√3x +√3x+√3√3=0
x(x+√3)+√3(x+√3)=0
(x+√3)(x+√3)=0
X+√3=0
X=-√3
X+√3=0
X=-√3
Hope it helps you!
Here is your answer,
x^2 + 2√3x + 3=0
x^2 +√3x +√3x+√3√3=0
x(x+√3)+√3(x+√3)=0
(x+√3)(x+√3)=0
X+√3=0
X=-√3
X+√3=0
X=-√3
Hope it helps you!
Similar questions