X^2+2x+1=8x^2 what is the solution of this math
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Answered by
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Answer:
Step-by-step explanation:
-7x²+2x+1=0
By the quadratic formula we get,
x = -2±√2²-4(-7)÷2(-7)
x = -2±√4+28 ÷ -14
x = -2±4√2 ÷ -14
x = -1±2√2 ÷ -7
The possible values of x are -1+2√2÷ -7 and -1+2√2÷ -7
Answered by
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Step-by-step explanation:
x^2+2x+1=8x^2
(x+1)^2=(2×root(2)×x)^2
x+1=2×root(2) ×x
x(1-2×root(2))= -1
x= -1/(1-2×root(2))
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