Question

X^2-2x+1 find the zeroes of the polynomial

Answer 1

Step-by-step explanation:

We Have :-

$x^{2} - 2x + 1$

To Find :-

$zeroes$

Method Used :-

$middle \: term \: splitting$

Solution :-

$x^{2} - 2x + 1 \\ \\ \\ x^{2} - x - x + 1 \\ \\ \\ x(x - 1) - 1(x - 1) \\ \\ \\ (x - 1)(x - 1) \\ \\ \\ x - 1 = 0 \\ \\ \\ x = 1$

Answer 2

$\sf{ {x}^{2} - 2x + 1 } \\ \\ \frak{ \red{ \underline{by \: middle \: term \: split \: method : }}} \\ \\ \rightarrow \frak{ {x}^{2} - (1 + 1)x + 1 = 0 } \\ \\ \rightarrow \frak{ {x}^{2} - x - x + 1 = 0 } \\ \\ \rightarrow \frak{x(x - 1) - 1(x - 1) = 0} \\ \\ \rightarrow \frak{(x - 1)(x - 1) = 0} \\ \\ \sf{x - 1 = 0} \\ \\ \boxed{\rightarrow \red{ \frak{x = 1}}}$