Question

x^2+2x-120=0 by splitting the middle the middle term​

Answer 1

SOLUTION :

Given that,

${x}^{2} + 2x - 120 = 0$

We have to split the middle term,

${x}^{2} + (12 - 10)x - 120 = 0$

${x}^{2} + 12x - 10x - 120 = 0$

Now let's take common.

$x(x + 12) - 10(x + 12)$

$(x + 12)(x - 10)$

Now let us equate the terms with zero.

$x + 12 = 0$

$x = - 12$

Also,

$x - 10 = 0$

$x = 10$

Hence, by middle term factorisation we get -12 and 10 as the values of x.

Answer 2

Answer:

${x}^{2} + 12x - 10x - 120 = 0$

$x(x + 12) - 10(x + 12) = 0$

$(x + 12)(x - 10) = 0$

$(x + 12) = 0 \: \: (x - 10) = 0$

$x = - 12$

$x = 10$

HOPE IT HELPS