x^2 + 2x - 160 = 0 ?
Answers
Answer:
Simplifying x2 + 2x + -160 = 0 Reorder the terms: -160 + 2x + x2 = 0 Solving -160 + 2x + x2 = 0 Solving for variable 'x'. Begin completing the square. Move the constant term to the right: Add '160' to each side of the equation. -160 + 2x + 160 + x2 = 0 + 160 Reorder the terms: -160 + 160 + 2x + x2 = 0 + 160 Combine like terms: -160 + 160 = 0 0 + 2x + x2 = 0 + 160 2x + x2 = 0 + 160 Combine like terms: 0 + 160 = 160 2x + x2 = 160 The x term is 2x. Take half its coefficient (1). Square it (1) and add it to both sides. Add '1' to each side of the equation. 2x + 1 + x2 = 160 + 1 Reorder the terms: 1 + 2x + x2 = 160 + 1 Combine like terms: 160 + 1 = 161 1 + 2x + x2 = 161 Factor a perfect square on the left side: (x + 1)(x + 1) = 161 Calculate the square root of the right side: 12.68857754 Break this problem into two subproblems by setting (x + 1) equal to 12.68857754 and -12.68857754.
Subproblem 1
x + 1 = 12.68857754 Simplifying x + 1 = 12.68857754 Reorder the terms: 1 + x = 12.68857754 Solving 1 + x = 12.68857754 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + x = 12.68857754 + -1 Combine like terms: 1 + -1 = 0 0 + x = 12.68857754 + -1 x = 12.68857754 + -1 Combine like terms: 12.68857754 + -1 = 11.68857754 x = 11.68857754 Simplifying x = 11.68857754