(x^2-2x)^2-23(x^2-2x)+120 :factorise answer:(x+2)(x-4)(x+3)(x-5)
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Answered by
166
Hi ,
( x² - 2x )² - 23(x² - 2x ) + 120
Let a = x² - 2x
= a² - 23a + 120
= a² -15a - 8a + 120
= a( a - 15 ) - 8 ( a - 15 )
= ( a - 15 )( a - 8 )
= ( x² - 2x - 15 ) ( x² - 2x - 8 )
= [ x2 + 3x - 5x - 15 ] ( x² -4x + 2x - 8 )
= [ x ( x + 3 ) - 5 ( x + 3 ) ] [ x ( x - 4 ) + 2(x - 4 )]
= ( x + 3 )( x - 5 ) ( x - 4 ) ( x + 2 )
= ( x - 5 ) ( x - 4 ) ( x + 2 ) ( x + 3 )
I hope this helps you.
: )
( x² - 2x )² - 23(x² - 2x ) + 120
Let a = x² - 2x
= a² - 23a + 120
= a² -15a - 8a + 120
= a( a - 15 ) - 8 ( a - 15 )
= ( a - 15 )( a - 8 )
= ( x² - 2x - 15 ) ( x² - 2x - 8 )
= [ x2 + 3x - 5x - 15 ] ( x² -4x + 2x - 8 )
= [ x ( x + 3 ) - 5 ( x + 3 ) ] [ x ( x - 4 ) + 2(x - 4 )]
= ( x + 3 )( x - 5 ) ( x - 4 ) ( x + 2 )
= ( x - 5 ) ( x - 4 ) ( x + 2 ) ( x + 3 )
I hope this helps you.
: )
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27
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