Question

(x^2-2x)^2 - 4(x^2-2x) +3 = 0. SOLVE THIS BY USING QUADRATIC FORMULA...​

Answer 1

Step-by-step explanation:

For equation ax 2 +bx+c=0Roots are given as = 2a−b± b 2 −4ac Now let us compare ax 2 +bx+c=0 with x 2 −2x+3=0 to find the values of a,b,cAfter it we can directly put a,b,c into the formula to find the rootsBy comparing a=1,b=−2,c=3So roots = 2×1−(−2)± (−2) 2 −4(1)(3)

−4(1)(3) = 22± 4−12

= 22± −8

=1±i 2

=1±i 2

=1±i 2 Hence the roots of the equation x 2 −2x+3=0 are imaginary

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