x^2+2x+ 3=0 find roots
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Answered by
1
Answer:
Step-by
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2
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x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}
x=2a−b±b2−4ac
Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.
2
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2
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3
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0
x^{2}+2x+3=0
x2+2x+3=0
=
1
a={\color{#c92786}{1}}
a=1
=
2
b={\color{#e8710a}{2}}
b=2
=
3
c={\color{#129eaf}{3}}
c=3
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2
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3
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1
-step explanation:
Answered by
1
The answer will be in the scientific calculator
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