Question

x^2+2x+ 3=0 find roots ​

Answer 1

Answer:

Step-by

=

−

±

2

−

4

√

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac​​

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

2

+

2

+

3

=

0

x^{2}+2x+3=0

x2+2x+3=0

=

1

a={\color{#c92786}{1}}

a=1

=

2

b={\color{#e8710a}{2}}

b=2

=

3

c={\color{#129eaf}{3}}

c=3

=

−

2

±

2

2

−

4

⋅

1

⋅

3

√

2

⋅

1

-step explanation:

Answer 2

The answer will be in the scientific calculator