Math, asked by someone46, 4 months ago

(x + 2)(2x – 3) = (2x + 1)(x – 2)​

Answers

Answered by amantripathi1011
2
I hope that this would be the right answer of your question
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Answered by suraj5070
145

 \sf \bf \huge {\boxed {\mathbb {QUESTION}}}

 \sf \bf (x + 2)(2x - 3) = (2x + 1)(x - 2)

 \sf \bf \huge {\boxed {\mathbb {ANSWER}}}

 \sf \bf \implies (x + 2)(2x - 3) = (2x + 1)(x - 2)

 \sf \bf \implies x(2x-3)+2(2x-3)=2x(x-2)+1(x-2)

 \sf \bf \implies 2{x}^{2}-3x+4x-6=2{x}^{2}-4x+x-2

 \sf \bf \implies 2{x}^{2}+1x-6=2{x}^{2}-3x-2

 \sf \bf \implies 2{x}^{2}-2{x}^{2}+1x+3x-6+2=0

 \sf \bf \implies \cancel {2{x}^{2}-2{x}^{2}} +1x+3x-6+2=0

 \sf \bf \implies 4x-4=0

 \sf \bf \implies 4x=4

 \sf \bf \implies x=\cancel{\dfrac{4}{4}}

 \implies {\boxed {\boxed {\sf \bf x=1}}}

 \sf \bf \huge {\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU}}}

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 \sf \bf \huge {\boxed {\mathbb {EXTRA\:INFORMATION}}}

 \sf \bf {Identities}

 \sf \bf {(a+b)}^{2}={a}^{2}+2ab+{b}^{2}

 \sf \bf {(a-b)}^{2}={a}^{2}-2ab+{b}^{2}

 \sf \bf (a+b) (a-b) ={a}^{2}-{b}^{2}

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