Question

(x+2)(2x-3)-2x^2+6/x-5=2​

Answer 1

Answer:

$(x + 2)(2x - 3) - {2x}^{2} + \frac{6}{x} - 5 = 2$

$x(2x - 3) + 2(2x - 3) - {2x}^{2} + \frac{6}{x} = 2 + 5$

${2x}^{2} - 3x + 4x - 12 - {2x}^{2} + \frac{6}{x} = 7$

$x - 12 + \frac{6}{x} = 7$

$x - \frac{12 + 12}{2x} = 7$

$x + \frac{24}{2x} = 7$

$x = 7 + \frac{2x}{24}$

$x = \frac{168}{2x}$

$x = \frac{84}{x}$

${x}^{2} = 84$

$x = 9.1$

Answer 2

Answer

= ( x + 2 ) ( 2x - 3 ) - 2x² + 6/x - 5 = 2

= x( 2x - 3 )+2( 3x - 3 ) - 2x² + 6/x = 2+5

= 2x² - 3x + 4x = 12 - 2x² + 6/x = 7

= x - 12 + 6/x = 7

= x - 12 + 12/2x = 7

= x + 24/2x = 7

= x = 7 + 2x/24

= x = 168/2x

= x = 84/x

= x² = 84

= x = 9.1