X^2+2x^3-5x+2 divided by x+1 without actual division
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This answer is very much hard
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Let p(f) be x²+2x³-5x+2
Let f(x) be x+1.
Now, x+1=0 ⇒ x= -1
Substitute the value of x in p(f).
p(f) = (-1)²+2(-1)³-5(-1)+2
= 1-2+5+2
= 6.
Thus, the quotient is 6.
The quotient is a whole number, the remainder is 0.
HOPE THIS HELPS :D
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