X^2 - 2x + 4 = 0 alfa ^6 + beta^6
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Answer:
x^2
δ
=b
2
−4
a
c
=(4
(
1
)
(
−
4
)
=
4
+
16
=
20
x1
=
−
b
+
√δ
/2
a = 2
+
√
20
/2
=
2
+
√
4
⋅
5
/2
=
2
+
2
√
5/
2
x
1=
(
1
+
√
5
) x
2
=
−
b
−
√
δ
/2
a
=2-0/2=2-√
4
⋅
5/
2
=
2
−
√
5
/2
x
2
=
(
1
−
√
5
)
x
2
−
2
x
−
4
=
0
⇒
(
x
−
x
1
)
(
x
−
x
2
)
=
0
⇒
(
x
−
(
1
+
√
5
)
)
(
x
−
(
1
−
√
5
)
)=
0
⇒
x
−
(
1
+
√
5
)
=
0
⇒
x
=
1
+
√
5
OR
x
−
(
1
−
√
5
)
=
0
⇒
x
=
1
−
√
5
α+β=2
αβ=4
(α^3)^2 +(β^3)^2
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