(x + 2) (2x + 4) = (x – 4) (2x - 3) + 53
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Step-by-step explanation:
(x+2)(2x+4)=(x-4)(2x-3)+53
We move all terms to the left:
(x+2)(2x+4)-((x-4)(2x-3)+53)=0
We multiply parentheses ..
(+2x^2+4x+4x+8)-((x-4)(2x-3)+53)=0
We calculate terms in parentheses: -((x-4)(2x-3)+53), so:
(x-4)(2x-3)+53
We multiply parentheses ..
(+2x^2-3x-8x+12)+53
We get rid of parentheses
2x^2-3x-8x+12+53
We add all the numbers together, and all the variables
2x^2-11x+65
Back to the equation:
-(2x^2-11x+65)
We get rid of parentheses
2x^2-2x^2+4x+4x+11x+8-65=0
We add all the numbers together, and all the variables
19x-57=0
We move all terms containing x to the left, all other terms to the right
19x=57
x=57/19
x=3
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