Math, asked by mugdha10, 1 year ago

x^2+2x-5=0 solve by completing square method

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Answered by Anonymous

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Answered by abdul9838

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$Hola \\ \\ Hey Dude here is Ans. \\ \\ \huge \: Question \\ \\ {x}^{2} + 2x - 5 = 0 \\ \\ \huge \: Answer \\ \\ \huge \: Method \: name \\ \\ \underline{completing \: square \: method} \\ \\ $

$\bf \: {x}^{2} + 2x - 5 = 0\\ \\ \bf \: (x)^{2} + 2 \times x \times 1 + {1}^{2} - {1}^{2} - 5 = 0 \\ \\ \bf \: ( {x + 1)}^{2} - 1 - 5 = 0 \\ \\ \bf \: ( {x + 1)}^{2} - 6 = 0 \\ \\ \bf \: ( {x + 1)}^{2} = 6 \\ \\ \bf \: x + 1 = \pm \: \sqrt{6} \\ \\ \bf \: x = \sqrt{6} - 1 \\ \\ \bf \: x = - (\sqrt{6} + 1) \: ans$

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$Thanks \: for \: asking \\ \\ Abdul \: is \: here \\ \\ Follow \: me$

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x^2+2x-5=0 solve by completing square method​

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x^2+2x-5=0 solve by completing square method