x^2 - 2x - 80 a find the zeros of the polynomial and verify the relation between zeros and the coefficients
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Answered by
0
Answer:
x
2
−2x−8
Factorize the equation, we get (x+2)(x−4)
So, the value of x
2
−2x−8 is zero when x+2=0,x−4=0, i.e., when x=−2 or x=4.
Therefore, the zeros of x
2
−2x−8 are -2 and 4.
Now,
⇒Sum of zeroes =−2+4=2=−
1
2
=−
Coefficient of x
2
Coefficient of x
⇒Product of zeros =(−2)×(4)=−8 =
1
−8
=
Coefficient of x
2
Constant term
Answered by
0
Answer:
x^2-2x-80
x^2-10x+8x-80
x(x-10)+8(x-10)
(x-10)(x+8)
x=-8(x) because it is negative
x=10
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