Math, asked by hardi36300, 21 days ago

x^2 - 2x - 80 a find the zeros of the polynomial and verify the relation between zeros and the coefficients​

Answers

Answered by choprasiddharth10
0

Answer:

x

2

−2x−8

Factorize the equation, we get (x+2)(x−4)

So, the value of x

2

−2x−8 is zero when x+2=0,x−4=0, i.e., when x=−2 or x=4.

Therefore, the zeros of x

2

−2x−8 are -2 and 4.

Now,

⇒Sum of zeroes =−2+4=2=−

1

2

=−

Coefficient of x

2

Coefficient of x

⇒Product of zeros =(−2)×(4)=−8 =

1

−8

=

Coefficient of x

2

Constant term

Answered by manansheoranhr123
0

Answer:

x^2-2x-80

x^2-10x+8x-80

x(x-10)+8(x-10)

(x-10)(x+8)

x=-8(x) because it is negative

x=10

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