Question

x^2+2x-a(a+2)=0. find the value of x​

Answer 1

Answer:

Before finding the roots of a quadratic equation, just find the determinant given by

det=b^2-4*a*c.

For this problem, det=4+8=12>0

So the roots are real and distinct.

So the roots would be

x=(-b+(det)^(1/2))/(2*a)

x=(-b-(det)^(1/2))/(2*a)

So x=(-2+2*(3^(1/2)))/2

x=(-2-2*(3^(1/2)))/2

the answer will be 1+/-3^1/2

How do I solve X^2+2X-2=0 by Quadratic formula?