Question

x^2+2xy+y^2-1 How to factorise it?

Answer 1

Answer & Step-by-step explanation:

= x^2+2xy+y^2-1

= (x+y)^2 - (1)^2

Using the formula, (a^2-b^2) = (a+b)(a-b)

= (x+y+1)(x+y-1)

Hope this helps.

Answer 2

Answer:

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' 1 - x^2 - 2 x y - y^2 '

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= 1 - ( x^2 + 2 x y + y^2 )

= 1 - ( x + y )^2

= ( 1)^2 - ( x + y )^2

= { 1 - ( x + y ) } { 1 + (x + y ) }

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= ( 1 - x - y ) ( 1 + x + y )

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