Question

x^2- 2xy+y^2+z^2
factorise it ​

Answer 1

Answer:

Step-by-step explanation:

x^2- 2xy+y^2-z^2

=(x-y)²-z²

=(x-y+z)(x-y-z)

Answer 2

Correct Question :

›»› x² - 2xy + y² - z² factorise it

Answer :

›»› (x - y + z)(x - y - z)

Given :

• x² - 2xy + y² - z²

To Find :

• Factorize the expression.

Solution :

→ x² - 2xy + y² - z²

Change the term in the middle,

→ x² - (2xy) + y² - z²

Organize the expression using A² ± 2AB + B² = (A ± B)²,

→ (x - y)² - z²

Organize by using A² - B² (A + B)(A - B)

→ ((x - y) + z) ((x - y) - z)

Get rid of unnecessary parenthese,

→ (x - y) + z) ((x - y) - z)

Get rid of unnecessary parenthese,

→ (x - y) + z) (x - y) - z)

║Hence, the factorization of x² - 2xy + y² - z² is (x - y) + z) (x - y) - z).║