x^2+2xy+y^2+z^2 if x=2,y=1,z=-3
Answers
Answered by
1
Answer:
18
Step-by-step explanation:
x^2+2xy+y^2+z^2
2^2+2(2)(1)+1^2+(-3)^2
4+4+1+9=18
Answered by
1
Answer:
put the value of X=2,y=1and z=-3
4+4+1+9=18
so 28 is the answer of your question
Similar questions