Math, asked by vaishnaviy400, 5 months ago

x^2+2xy+y^2+z^2 if x=2,y=1,z=-3​

Answers

Answered by Thenavi
1

Answer:

18

Step-by-step explanation:

x^2+2xy+y^2+z^2

2^2+2(2)(1)+1^2+(-3)^2

4+4+1+9=18

Answered by smile935
1

Answer:

put the value of X=2,y=1and z=-3

4+4+1+9=18

so 28 is the answer of your question

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